For problem one, write the expression for the equilibrium constant for
each of the reactions. For problem two, from the data provided, calculate
the value of the equilibrium constant for the reactions listed in problem
one. Two of the problems require you to find the concentration of one of
the chemicals in the equation given the other concentrations and the
equilibrium constant.
1)
H_{2} + Cl_{2} ↔ 2HCl
2SO_{2} + O_{2} ↔ 2SO_{3}
N_{2} + 3H_{2} ↔ 2NH_{3}
2CO + O_{2} ↔ 2CO_{2}
N_{2} + ½ O_{2} ↔ N_{2}O
HCN ↔ H^{+} + CN^{–}
H_{2}SO_{4} ↔ H^{+} +
HSO_{4}^{–}
2)
[H2] = [Cl_{2}] = 1.0 × 10^{–2} M;
[HCl] = 1.0 × 10^{–4} M This is read: “The concentration of
hydrogen gas equals the concentration of chlorine gas equals 1.0
× 10^{–2} M; The concentration of HCl is 1.0
× 10^{–4} M”
[H_{2}] = 2.0 × 10^{–2} M;
[Cl_{2}] = 2.5 × 10^{–2} M;
[HCl] = 1.5 × 10^{–3} M
[SO_{2}] = 1.0 × 10^{–3} M;
[O_{2}] = 2.0 × 10^{–3} M;
[SO_{3}] = 3.0 × 10^{–3} M
[N_{2}] = 4.4 × 10^{–2} M;
[H_{2}] = 1.2 × 10^{–1} M;
[NH_{3}] = 3.4 × 10^{–3} M
[N_{2}] = 0.25 M; [H_{2}] = 0.10 M;
[NH_{3}] = 0.010 M
[CO] = 0.5 M; [O_{2}] = 0.5 M;
[CO_{2}] = 2.5 M
Find [SO_{3}] if [O_{2}] = 2.4 ×
10^{–3} M;
[SO_{2}] = 4.1 × 10^{–4} M
and K_{c} = 4.5 × 10^{3}
Find [CO] if [O_{2}] = 1.3 × 10^{–3}
M;
[CO_{2}] = 2.5 x 10^{–4} M
and K_{c} = 3.6 x 10^{–3}
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Solubility Product
For problem three write the solubility product expression for the
equations given. For problem four, use the data provided to find the
required quantity.